Base | Representation |
---|---|
bin | 11110000011000011010101… |
… | …111001110001011011111001 |
3 | 122022220112012100001101021211 |
4 | 132003003111321301123321 |
5 | 114310131014432030113 |
6 | 1145021221410203121 |
7 | 36556414334655502 |
oct | 3603032571613371 |
9 | 568815170041254 |
10 | 132151142455033 |
11 | 3911aa91819579 |
12 | 129a393a2834a1 |
13 | 5897a50c927b0 |
14 | 248c21402dba9 |
15 | 104284b5c5b3d |
hex | 7830d5e716f9 |
132151142455033 has 16 divisors (see below), whose sum is σ = 156320309335680. Its totient is φ = 110540790163584.
The previous prime is 132151142455019. The next prime is 132151142455037. The reversal of 132151142455033 is 330554241151231.
It is a cyclic number.
It is not a de Polignac number, because 132151142455033 - 241 = 129952119199481 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132151142455037) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11630969716 + ... + 11630981077.
It is an arithmetic number, because the mean of its divisors is an integer number (9770019333480).
Almost surely, 2132151142455033 is an apocalyptic number.
132151142455033 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
132151142455033 is a deficient number, since it is larger than the sum of its proper divisors (24169166880647).
132151142455033 is a wasteful number, since it uses less digits than its factorization.
132151142455033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23261950848.
The product of its (nonzero) digits is 216000, while the sum is 40.
The spelling of 132151142455033 in words is "one hundred thirty-two trillion, one hundred fifty-one billion, one hundred forty-two million, four hundred fifty-five thousand, thirty-three".
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