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132153261446543 is a prime number
BaseRepresentation
bin11110000011000101010100…
…001101000101010110001111
3122022220201200000022022011212
4132003011110031011112033
5114310144334412242133
61145022211543405035
736556521005051351
oct3603052415052617
9568821600268155
10132153261446543
1139120979949227
12129a422ba5377b
135897ccac9ca1c
14248c3756210d1
151042922640148
hex78315434558f

132153261446543 has 2 divisors, whose sum is σ = 132153261446544. Its totient is φ = 132153261446542.

The previous prime is 132153261446539. The next prime is 132153261446651. The reversal of 132153261446543 is 345644162351231.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132153261446543 - 22 = 132153261446539 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132153261446491 and 132153261446500.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132153261446443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66076630723271 + 66076630723272.

It is an arithmetic number, because the mean of its divisors is an integer number (66076630723272).

Almost surely, 2132153261446543 is an apocalyptic number.

132153261446543 is a deficient number, since it is larger than the sum of its proper divisors (1).

132153261446543 is an equidigital number, since it uses as much as digits as its factorization.

132153261446543 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6220800, while the sum is 50.

The spelling of 132153261446543 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, two hundred sixty-one million, four hundred forty-six thousand, five hundred forty-three".