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132153442405637 is a prime number
BaseRepresentation
bin11110000011000101011110…
…111111011000110100000101
3122022220202010121210222101112
4132003011132333120310011
5114310200222223440022
61145022241530134405
736556525333143032
oct3603053677306405
9568822117728345
10132153442405637
1139120a620064a4
12129a4280581405
13589802961b303
14248c391688389
1510429334878e2
hex78315efd8d05

132153442405637 has 2 divisors, whose sum is σ = 132153442405638. Its totient is φ = 132153442405636.

The previous prime is 132153442405597. The next prime is 132153442405711. The reversal of 132153442405637 is 736504244351231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 66825245958241 + 65328196447396 = 8174671^2 + 8082586^2 .

It is a cyclic number.

It is not a de Polignac number, because 132153442405637 - 218 = 132153442143493 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132153442405037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66076721202818 + 66076721202819.

It is an arithmetic number, because the mean of its divisors is an integer number (66076721202819).

Almost surely, 2132153442405637 is an apocalyptic number.

It is an amenable number.

132153442405637 is a deficient number, since it is larger than the sum of its proper divisors (1).

132153442405637 is an equidigital number, since it uses as much as digits as its factorization.

132153442405637 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7257600, while the sum is 50.

Adding to 132153442405637 its reverse (736504244351231), we get a palindrome (868657686756868).

The spelling of 132153442405637 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, four hundred forty-two million, four hundred five thousand, six hundred thirty-seven".