Base | Representation |
---|---|
bin | 11110000011000101011110… |
… | …111111011000110101001111 |
3 | 122022220202010121210222111021 |
4 | 132003011132333120311033 |
5 | 114310200222223440321 |
6 | 1145022241530135011 |
7 | 36556525333143166 |
oct | 3603053677306517 |
9 | 568822117728437 |
10 | 132153442405711 |
11 | 39120a62006561 |
12 | 129a4280581467 |
13 | 589802961b35c |
14 | 248c3916883dd |
15 | 1042933487941 |
hex | 78315efd8d4f |
132153442405711 has 2 divisors, whose sum is σ = 132153442405712. Its totient is φ = 132153442405710.
The previous prime is 132153442405637. The next prime is 132153442405739. The reversal of 132153442405711 is 117504244351231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132153442405711 - 225 = 132153408851279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132153442405781) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66076721202855 + 66076721202856.
It is an arithmetic number, because the mean of its divisors is an integer number (66076721202856).
Almost surely, 2132153442405711 is an apocalyptic number.
132153442405711 is a deficient number, since it is larger than the sum of its proper divisors (1).
132153442405711 is an equidigital number, since it uses as much as digits as its factorization.
132153442405711 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 403200, while the sum is 43.
Adding to 132153442405711 its reverse (117504244351231), we get a palindrome (249657686756942).
The spelling of 132153442405711 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, four hundred forty-two million, four hundred five thousand, seven hundred eleven".
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