Base | Representation |
---|---|
bin | 11110000011000101011110… |
… | …111111110101100100001111 |
3 | 122022220202010122000221221101 |
4 | 132003011132333311210033 |
5 | 114310200222241222112 |
6 | 1145022241532443531 |
7 | 36556525334143264 |
oct | 3603053677654417 |
9 | 568822118027841 |
10 | 132153442523407 |
11 | 39120a62086a28 |
12 | 129a42806195a7 |
13 | 589802965cab6 |
14 | 248c3916b926b |
15 | 10429334ac757 |
hex | 78315eff590f |
132153442523407 has 2 divisors, whose sum is σ = 132153442523408. Its totient is φ = 132153442523406.
The previous prime is 132153442523381. The next prime is 132153442523437. The reversal of 132153442523407 is 704325244351231.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132153442523407 - 215 = 132153442490639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132153442523437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66076721261703 + 66076721261704.
It is an arithmetic number, because the mean of its divisors is an integer number (66076721261704).
Almost surely, 2132153442523407 is an apocalyptic number.
132153442523407 is a deficient number, since it is larger than the sum of its proper divisors (1).
132153442523407 is an equidigital number, since it uses as much as digits as its factorization.
132153442523407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2419200, while the sum is 46.
Adding to 132153442523407 its reverse (704325244351231), we get a palindrome (836478686874638).
The spelling of 132153442523407 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, four hundred forty-two million, five hundred twenty-three thousand, four hundred seven".
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