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1321886394989 is a prime number
BaseRepresentation
bin10011001111000110100…
…100011010101001101101
311200101000112110111220222
4103033012210122221231
5133124210404114424
62451133301021125
7164334401652206
oct23170644325155
94611015414828
101321886394989
1146a677454736
121942350b47a5
1397865551214
1447da01d65ad
15245ba5b2e5e
hex133c691aa6d

1321886394989 has 2 divisors, whose sum is σ = 1321886394990. Its totient is φ = 1321886394988.

The previous prime is 1321886394977. The next prime is 1321886394991. The reversal of 1321886394989 is 9894936881231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1090677366025 + 231209028964 = 1044355^2 + 480842^2 .

It is a cyclic number.

It is not a de Polignac number, because 1321886394989 - 24 = 1321886394973 is a prime.

It is a Sophie Germain prime.

Together with 1321886394991, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1321886894989) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660943197494 + 660943197495.

It is an arithmetic number, because the mean of its divisors is an integer number (660943197495).

Almost surely, 21321886394989 is an apocalyptic number.

It is an amenable number.

1321886394989 is a deficient number, since it is larger than the sum of its proper divisors (1).

1321886394989 is an equidigital number, since it uses as much as digits as its factorization.

1321886394989 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 161243136, while the sum is 71.

The spelling of 1321886394989 in words is "one trillion, three hundred twenty-one billion, eight hundred eighty-six million, three hundred ninety-four thousand, nine hundred eighty-nine".