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132200543453 = 1112018231223
BaseRepresentation
bin111101100011111000…
…1000011010011011101
3110122020021122102202012
41323013301003103131
54131221314342303
6140422044241005
712360024035636
oct1730761032335
9418207572665
10132200543453
115107a83aa90
1221755840165
13c60aa66654
14658184888d
15368b13b5d8
hex1ec7c434dd

132200543453 has 4 divisors (see below), whose sum is σ = 144218774688. Its totient is φ = 120182312220.

The previous prime is 132200543417. The next prime is 132200543467. The reversal of 132200543453 is 354345002231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132200543453 - 210 = 132200542429 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132205543453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6009115601 + ... + 6009115622.

It is an arithmetic number, because the mean of its divisors is an integer number (36054693672).

Almost surely, 2132200543453 is an apocalyptic number.

It is an amenable number.

132200543453 is a deficient number, since it is larger than the sum of its proper divisors (12018231235).

132200543453 is a wasteful number, since it uses less digits than its factorization.

132200543453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12018231234.

The product of its (nonzero) digits is 43200, while the sum is 32.

Adding to 132200543453 its reverse (354345002231), we get a palindrome (486545545684).

The spelling of 132200543453 in words is "one hundred thirty-two billion, two hundred million, five hundred forty-three thousand, four hundred fifty-three".

Divisors: 1 11 12018231223 132200543453