Base | Representation |
---|---|
bin | 11110000011110001111110… |
… | …010101110000001010111111 |
3 | 122100002022102211121201202021 |
4 | 132003301332111300022333 |
5 | 114311441041012034211 |
6 | 1145100222051541011 |
7 | 36563136204415006 |
oct | 3603617625601277 |
9 | 570068384551667 |
10 | 132201213002431 |
11 | 3913a246296961 |
12 | 129b15928ba767 |
13 | 589c6a0533231 |
14 | 2490803c85c3d |
15 | 1043ccc253771 |
hex | 783c7e5702bf |
132201213002431 has 2 divisors, whose sum is σ = 132201213002432. Its totient is φ = 132201213002430.
The previous prime is 132201213002429. The next prime is 132201213002449. The reversal of 132201213002431 is 134200312102231.
It is a weak prime.
It is an emirp because it is prime and its reverse (134200312102231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132201213002431 - 21 = 132201213002429 is a prime.
It is a super-3 number, since 3×1322012130024313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 132201213002429, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 132201213002396 and 132201213002405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132201213002461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66100606501215 + 66100606501216.
It is an arithmetic number, because the mean of its divisors is an integer number (66100606501216).
Almost surely, 2132201213002431 is an apocalyptic number.
132201213002431 is a deficient number, since it is larger than the sum of its proper divisors (1).
132201213002431 is an equidigital number, since it uses as much as digits as its factorization.
132201213002431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 132201213002431 its reverse (134200312102231), we get a palindrome (266401525104662).
The spelling of 132201213002431 in words is "one hundred thirty-two trillion, two hundred one billion, two hundred thirteen million, two thousand, four hundred thirty-one".
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