Base | Representation |
---|---|
bin | 11000100111111110… |
… | …00010011010111111 |
3 | 1021010100010102211012 |
4 | 30103333002122333 |
5 | 204033332201413 |
6 | 10023454345435 |
7 | 645415536413 |
oct | 142377023277 |
9 | 37110112735 |
10 | 13220193983 |
11 | 5674500457 |
12 | 268b4bb27b |
13 | 1328ba97b9 |
14 | 8d5ac6d43 |
15 | 5259497a8 |
hex | 313fc26bf |
13220193983 has 2 divisors, whose sum is σ = 13220193984. Its totient is φ = 13220193982.
The previous prime is 13220193937. The next prime is 13220193991. The reversal of 13220193983 is 38939102231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13220193983 - 222 = 13215999679 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13220193983.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13220193683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6610096991 + 6610096992.
It is an arithmetic number, because the mean of its divisors is an integer number (6610096992).
Almost surely, 213220193983 is an apocalyptic number.
13220193983 is a deficient number, since it is larger than the sum of its proper divisors (1).
13220193983 is an equidigital number, since it uses as much as digits as its factorization.
13220193983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69984, while the sum is 41.
The spelling of 13220193983 in words is "thirteen billion, two hundred twenty million, one hundred ninety-three thousand, nine hundred eighty-three".
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