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1322020021031 = 6313120940901
BaseRepresentation
bin10011001111001110100…
…010001010001100100111
311200101100211220102101122
4103033032202022030213
5133124444111133111
62451154433044155
7164340613524413
oct23171642121447
94611324812348
101322020021031
1146a735922986
121942719b665b
1397887139298
1447db3c5bd43
15245c71aacdb
hex133ce88a327

1322020021031 has 4 divisors (see below), whose sum is σ = 1322041025064. Its totient is φ = 1321999017000.

The previous prime is 1322020021019. The next prime is 1322020021051. The reversal of 1322020021031 is 1301200202231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1322020021031 - 218 = 1322019758887 is a prime.

It is a super-2 number, since 2×13220200210312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1322020021051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10407320 + ... + 10533581.

It is an arithmetic number, because the mean of its divisors is an integer number (330510256266).

Almost surely, 21322020021031 is an apocalyptic number.

1322020021031 is a deficient number, since it is larger than the sum of its proper divisors (21004033).

1322020021031 is an equidigital number, since it uses as much as digits as its factorization.

1322020021031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21004032.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1322020021031 its reverse (1301200202231), we get a palindrome (2623220223262).

The spelling of 1322020021031 in words is "one trillion, three hundred twenty-two billion, twenty million, twenty-one thousand, thirty-one".

Divisors: 1 63131 20940901 1322020021031