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13220200315 = 57377720009
BaseRepresentation
bin11000100111111110…
…00011111101111011
31021010100010202111201
430103333003331323
5204033332402230
610023454435031
7645415564030
oct142377037573
937110122451
1013220200315
115674505193
12268b502a77
131328bac64a
148d5ac9387
1552594b5ca
hex313fc3f7b

13220200315 has 8 divisors (see below), whose sum is σ = 18130560480. Its totient is φ = 9065280192.

The previous prime is 13220200313. The next prime is 13220200349. The reversal of 13220200315 is 51300202231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13220200315 - 21 = 13220200313 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13220200292 and 13220200301.

It is not an unprimeable number, because it can be changed into a prime (13220200313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 188859970 + ... + 188860039.

It is an arithmetic number, because the mean of its divisors is an integer number (2266320060).

Almost surely, 213220200315 is an apocalyptic number.

13220200315 is a deficient number, since it is larger than the sum of its proper divisors (4910360165).

13220200315 is an equidigital number, since it uses as much as digits as its factorization.

13220200315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 377720021.

The product of its (nonzero) digits is 360, while the sum is 19.

Adding to 13220200315 its reverse (51300202231), we get a palindrome (64520402546).

The spelling of 13220200315 in words is "thirteen billion, two hundred twenty million, two hundred thousand, three hundred fifteen".

Divisors: 1 5 7 35 377720009 1888600045 2644040063 13220200315