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1322030121143 = 6263211085761
BaseRepresentation
bin10011001111001111001…
…000101100000010110111
311200101101112220120010212
4103033033020230002313
5133130004202334033
62451155433340035
7164341065421664
oct23171710540267
94611345816125
101322030121143
1146a7405a1286
1219427526761b
1397889264594
1447db532aa6b
15245c8003748
hex133cf22c0b7

1322030121143 has 4 divisors (see below), whose sum is σ = 1322241213168. Its totient is φ = 1321819029120.

The previous prime is 1322030121131. The next prime is 1322030121271. The reversal of 1322030121143 is 3411210302231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1322030121143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1322030121043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105536618 + ... + 105549143.

It is an arithmetic number, because the mean of its divisors is an integer number (330560303292).

Almost surely, 21322030121143 is an apocalyptic number.

1322030121143 is a deficient number, since it is larger than the sum of its proper divisors (211092025).

1322030121143 is an equidigital number, since it uses as much as digits as its factorization.

1322030121143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 211092024.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1322030121143 its reverse (3411210302231), we get a palindrome (4733240423374).

The spelling of 1322030121143 in words is "one trillion, three hundred twenty-two billion, thirty million, one hundred twenty-one thousand, one hundred forty-three".

Divisors: 1 6263 211085761 1322030121143