13220404031 has 2 divisors, whose sum is σ = 13220404032. Its totient is φ = 13220404030.

The previous prime is 13220404027. The next prime is 13220404033. The reversal of 13220404031 is 13040402231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13220404031 - 2² = 13220404027 is a prime.

It is a super-2 number, since 2×13220404031² (a number of 21 digits) contains 22 as substring.

Together with 13220404033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13220403994 and 13220404012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13220404033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6610202015 + 6610202016.

It is an arithmetic number, because the mean of its divisors is an integer number (6610202016).

Almost surely, 2^13220404031 is an apocalyptic number.

13220404031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13220404031 is an equidigital number, since it uses as much as digits as its factorization.

13220404031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 13220404031 its reverse (13040402231), we get a palindrome (26260806262).

The spelling of 13220404031 in words is "thirteen billion, two hundred twenty million, four hundred four thousand, thirty-one".