Base | Representation |
---|---|
bin | 1100000001100001111100… |
… | …1101100111101101010111 |
3 | 1201210212020201002020010221 |
4 | 3000120133031213231113 |
5 | 3213100421322020203 |
6 | 44041214424455211 |
7 | 2533100440242643 |
oct | 300303715475527 |
9 | 51725221066127 |
10 | 13220433001303 |
11 | 4237832856230 |
12 | 159626031a507 |
13 | 74b8b22a98b8 |
14 | 339c2db03c23 |
15 | 17dd618a8abd |
hex | c061f367b57 |
13220433001303 has 4 divisors (see below), whose sum is σ = 14422290546888. Its totient is φ = 12018575455720.
The previous prime is 13220433001301. The next prime is 13220433001361. The reversal of 13220433001303 is 30310033402231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13220433001303 - 21 = 13220433001301 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13220433001301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 600928772776 + ... + 600928772797.
It is an arithmetic number, because the mean of its divisors is an integer number (3605572636722).
Almost surely, 213220433001303 is an apocalyptic number.
13220433001303 is a deficient number, since it is larger than the sum of its proper divisors (1201857545585).
13220433001303 is a wasteful number, since it uses less digits than its factorization.
13220433001303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1201857545584.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 13220433001303 its reverse (30310033402231), we get a palindrome (43530466403534).
The spelling of 13220433001303 in words is "thirteen trillion, two hundred twenty billion, four hundred thirty-three million, one thousand, three hundred three".
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