Base | Representation |
---|---|
bin | 10011001111010011111… |
… | …001110101100011010001 |
3 | 11200101121010102121201022 |
4 | 103033103321311203101 |
5 | 133130140142122001 |
6 | 2451211412045225 |
7 | 164343056355215 |
oct | 23172371654321 |
9 | 4611533377638 |
10 | 1322110114001 |
11 | 46a781768086 |
12 | 194298003815 |
13 | 9789c9c1631 |
14 | 47dc1bd0945 |
15 | 245d005511b |
hex | 133d3e758d1 |
1322110114001 has 2 divisors, whose sum is σ = 1322110114002. Its totient is φ = 1322110114000.
The previous prime is 1322110113967. The next prime is 1322110114019. The reversal of 1322110114001 is 1004110112231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1153209663376 + 168900450625 = 1073876^2 + 410975^2 .
It is a cyclic number.
It is not a de Polignac number, because 1322110114001 - 26 = 1322110113937 is a prime.
It is not a weakly prime, because it can be changed into another prime (1322110110001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661055057000 + 661055057001.
It is an arithmetic number, because the mean of its divisors is an integer number (661055057001).
Almost surely, 21322110114001 is an apocalyptic number.
It is an amenable number.
1322110114001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1322110114001 is an equidigital number, since it uses as much as digits as its factorization.
1322110114001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1322110114001 its reverse (1004110112231), we get a palindrome (2326220226232).
The spelling of 1322110114001 in words is "one trillion, three hundred twenty-two billion, one hundred ten million, one hundred fourteen thousand, one".
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