Base | Representation |
---|---|
bin | 11000101000000101… |
… | …11000110010101101 |
3 | 1021010102000201002112 |
4 | 30110002320302231 |
5 | 204034111444432 |
6 | 10023532133405 |
7 | 645430241453 |
oct | 142402706255 |
9 | 37112021075 |
10 | 13221203117 |
11 | 567502a651 |
12 | 268b907265 |
13 | 1329170c15 |
14 | 8d5caa9d3 |
15 | 525a987b2 |
hex | 3140b8cad |
13221203117 has 2 divisors, whose sum is σ = 13221203118. Its totient is φ = 13221203116.
The previous prime is 13221203087. The next prime is 13221203123. The reversal of 13221203117 is 71130212231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11208245161 + 2012957956 = 105869^2 + 44866^2 .
It is a cyclic number.
It is not a de Polignac number, because 13221203117 - 26 = 13221203053 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13221203092 and 13221203101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13221203717) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6610601558 + 6610601559.
It is an arithmetic number, because the mean of its divisors is an integer number (6610601559).
Almost surely, 213221203117 is an apocalyptic number.
It is an amenable number.
13221203117 is a deficient number, since it is larger than the sum of its proper divisors (1).
13221203117 is an equidigital number, since it uses as much as digits as its factorization.
13221203117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 13221203117 its reverse (71130212231), we get a palindrome (84351415348).
The spelling of 13221203117 in words is "thirteen billion, two hundred twenty-one million, two hundred three thousand, one hundred seventeen".
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