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1322121443143 is a prime number
BaseRepresentation
bin10011001111010100100…
…101000011011101000111
311200101121220202012101011
4103033110211003131013
5133130201042140033
62451212454543051
7164343254561614
oct23172445033507
94611556665334
101322121443143
1146a7880a5906
1219429b967a87
13978a215a177
1447dc34dd50b
15245d1041ccd
hex133d4943747

1322121443143 has 2 divisors, whose sum is σ = 1322121443144. Its totient is φ = 1322121443142.

The previous prime is 1322121443131. The next prime is 1322121443243. The reversal of 1322121443143 is 3413441212231.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1322121443143 is a prime.

It is a super-2 number, since 2×13221214431432 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1322121443113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661060721571 + 661060721572.

It is an arithmetic number, because the mean of its divisors is an integer number (661060721572).

Almost surely, 21322121443143 is an apocalyptic number.

1322121443143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1322121443143 is an equidigital number, since it uses as much as digits as its factorization.

1322121443143 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13824, while the sum is 31.

Adding to 1322121443143 its reverse (3413441212231), we get a palindrome (4735562655374).

The spelling of 1322121443143 in words is "one trillion, three hundred twenty-two billion, one hundred twenty-one million, four hundred forty-three thousand, one hundred forty-three".