Base | Representation |
---|---|
bin | 10011001111010100100… |
… | …101000011011101000111 |
3 | 11200101121220202012101011 |
4 | 103033110211003131013 |
5 | 133130201042140033 |
6 | 2451212454543051 |
7 | 164343254561614 |
oct | 23172445033507 |
9 | 4611556665334 |
10 | 1322121443143 |
11 | 46a7880a5906 |
12 | 19429b967a87 |
13 | 978a215a177 |
14 | 47dc34dd50b |
15 | 245d1041ccd |
hex | 133d4943747 |
1322121443143 has 2 divisors, whose sum is σ = 1322121443144. Its totient is φ = 1322121443142.
The previous prime is 1322121443131. The next prime is 1322121443243. The reversal of 1322121443143 is 3413441212231.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1322121443143 is a prime.
It is a super-2 number, since 2×13221214431432 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1322121443113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661060721571 + 661060721572.
It is an arithmetic number, because the mean of its divisors is an integer number (661060721572).
Almost surely, 21322121443143 is an apocalyptic number.
1322121443143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1322121443143 is an equidigital number, since it uses as much as digits as its factorization.
1322121443143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 13824, while the sum is 31.
Adding to 1322121443143 its reverse (3413441212231), we get a palindrome (4735562655374).
The spelling of 1322121443143 in words is "one trillion, three hundred twenty-two billion, one hundred twenty-one million, four hundred forty-three thousand, one hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.113 sec. • engine limits •