Base | Representation |
---|---|
bin | 11000101000000111… |
… | …01100010010000101 |
3 | 1021010102102102101210 |
4 | 30110003230102011 |
5 | 204034140222041 |
6 | 10023540442033 |
7 | 645432110364 |
oct | 142403542205 |
9 | 37112372353 |
10 | 13221414021 |
11 | 5675164052 |
12 | 268b9a9319 |
13 | 1329215c0a |
14 | 8d5d237db |
15 | 525adb016 |
hex | 3140ec485 |
13221414021 has 4 divisors (see below), whose sum is σ = 17628552032. Its totient is φ = 8814276012.
The previous prime is 13221414013. The next prime is 13221414023. The reversal of 13221414021 is 12041412231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 13221414021 - 23 = 13221414013 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13221414023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2203569001 + ... + 2203569006.
It is an arithmetic number, because the mean of its divisors is an integer number (4407138008).
Almost surely, 213221414021 is an apocalyptic number.
It is an amenable number.
13221414021 is a deficient number, since it is larger than the sum of its proper divisors (4407138011).
13221414021 is an equidigital number, since it uses as much as digits as its factorization.
13221414021 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4407138010.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 13221414021 its reverse (12041412231), we get a palindrome (25262826252).
The spelling of 13221414021 in words is "thirteen billion, two hundred twenty-one million, four hundred fourteen thousand, twenty-one".
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