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132214500319997 is a prime number
BaseRepresentation
bin11110000011111110010110…
…010100110110001011111101
3122100010120201212001101211002
4132003332112110312023331
5114312200244040214442
61145110300345140045
736564116366641124
oct3603762624661375
9570116655041732
10132214500319997
1139144944673247
12129b408078a625
1358a0a0a2b2214
142491304842abb
151044308a0b732
hex783f965362fd

132214500319997 has 2 divisors, whose sum is σ = 132214500319998. Its totient is φ = 132214500319996.

The previous prime is 132214500319987. The next prime is 132214500320069. The reversal of 132214500319997 is 799913005412231.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131285626504036 + 928873815961 = 11457994^2 + 963781^2 .

It is an emirp because it is prime and its reverse (799913005412231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132214500319997 - 212 = 132214500315901 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132214500319987) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66107250159998 + 66107250159999.

It is an arithmetic number, because the mean of its divisors is an integer number (66107250159999).

Almost surely, 2132214500319997 is an apocalyptic number.

It is an amenable number.

132214500319997 is a deficient number, since it is larger than the sum of its proper divisors (1).

132214500319997 is an equidigital number, since it uses as much as digits as its factorization.

132214500319997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3674160, while the sum is 56.

The spelling of 132214500319997 in words is "one hundred thirty-two trillion, two hundred fourteen billion, five hundred million, three hundred nineteen thousand, nine hundred ninety-seven".