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132215143242253 is a prime number
BaseRepresentation
bin11110000011111110111100…
…101001011001101000001101
3122100010122101122211020100111
4132003332330221121220031
5114312203103132223003
61145110444233200021
736564141334456051
oct3603767451315015
9570118348736314
10132215143242253
1139145144578255
12129b421bb60011
1358a0ab05587a6
142491365d9dc61
1510443451a6e6d
hex783fbca59a0d

132215143242253 has 2 divisors, whose sum is σ = 132215143242254. Its totient is φ = 132215143242252.

The previous prime is 132215143242251. The next prime is 132215143242271. The reversal of 132215143242253 is 352242341512231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 69767881282089 + 62447261960164 = 8352717^2 + 7902358^2 .

It is a cyclic number.

It is not a de Polignac number, because 132215143242253 - 21 = 132215143242251 is a prime.

Together with 132215143242251, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132215143242251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66107571621126 + 66107571621127.

It is an arithmetic number, because the mean of its divisors is an integer number (66107571621127).

Almost surely, 2132215143242253 is an apocalyptic number.

It is an amenable number.

132215143242253 is a deficient number, since it is larger than the sum of its proper divisors (1).

132215143242253 is an equidigital number, since it uses as much as digits as its factorization.

132215143242253 is an evil number, because the sum of its binary digits is even.

The product of its digits is 345600, while the sum is 40.

Adding to 132215143242253 its reverse (352242341512231), we get a palindrome (484457484754484).

The spelling of 132215143242253 in words is "one hundred thirty-two trillion, two hundred fifteen billion, one hundred forty-three million, two hundred forty-two thousand, two hundred fifty-three".