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132217557590141 is a prime number
BaseRepresentation
bin11110000100000001001100…
…100011011010000001111101
3122100010212121220211211000122
4132010001030203122001331
5114312223024220341031
61145111524001104325
736564255222211142
oct3604011443320175
9570125556754018
10132217557590141
113914617339a591
12129b47946280a5
1358a10a67c8cca
1424915148b63c9
15104443711447b
hex78404c8da07d

132217557590141 has 2 divisors, whose sum is σ = 132217557590142. Its totient is φ = 132217557590140.

The previous prime is 132217557590093. The next prime is 132217557590147. The reversal of 132217557590141 is 141095755712231.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123431988900025 + 8785568690116 = 11109995^2 + 2964046^2 .

It is a cyclic number.

It is not a de Polignac number, because 132217557590141 - 226 = 132217490481277 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132217557590147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66108778795070 + 66108778795071.

It is an arithmetic number, because the mean of its divisors is an integer number (66108778795071).

Almost surely, 2132217557590141 is an apocalyptic number.

It is an amenable number.

132217557590141 is a deficient number, since it is larger than the sum of its proper divisors (1).

132217557590141 is an equidigital number, since it uses as much as digits as its factorization.

132217557590141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2646000, while the sum is 53.

The spelling of 132217557590141 in words is "one hundred thirty-two trillion, two hundred seventeen billion, five hundred fifty-seven million, five hundred ninety thousand, one hundred forty-one".