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1322185342897 is a prime number
BaseRepresentation
bin10011001111011000011…
…000110011111110110001
311200101210100222122100201
4103033120120303332301
5133130313421433042
62451223100315201
7164344661660356
oct23173030637661
94611710878321
101322185342897
1146a81017a721
121942b9242b01
13978b2471183
1447dcbbb462d
15245d69651b7
hex133d8633fb1

1322185342897 has 2 divisors, whose sum is σ = 1322185342898. Its totient is φ = 1322185342896.

The previous prime is 1322185342879. The next prime is 1322185342903. The reversal of 1322185342897 is 7982435812231.

It is a happy number.

Together with previous prime (1322185342879) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 935290146816 + 386895196081 = 967104^2 + 622009^2 .

It is a cyclic number.

It is not a de Polignac number, because 1322185342897 - 211 = 1322185340849 is a prime.

It is not a weakly prime, because it can be changed into another prime (1322185342837) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661092671448 + 661092671449.

It is an arithmetic number, because the mean of its divisors is an integer number (661092671449).

Almost surely, 21322185342897 is an apocalyptic number.

It is an amenable number.

1322185342897 is a deficient number, since it is larger than the sum of its proper divisors (1).

1322185342897 is an equidigital number, since it uses as much as digits as its factorization.

1322185342897 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5806080, while the sum is 55.

The spelling of 1322185342897 in words is "one trillion, three hundred twenty-two billion, one hundred eighty-five million, three hundred forty-two thousand, eight hundred ninety-seven".