Base | Representation |
---|---|
bin | 10011001111011001010… |
… | …000110011100000100111 |
3 | 11200101211101121100222022 |
4 | 103033121100303200213 |
5 | 133130331201133111 |
6 | 2451224343053355 |
7 | 164345230512641 |
oct | 23173120634047 |
9 | 4611741540868 |
10 | 1322200021031 |
11 | 46a81849560a |
12 | 19430214125b |
13 | 978b5510166 |
14 | 47dcdb15891 |
15 | 245d7db42db |
hex | 133d9433827 |
1322200021031 has 2 divisors, whose sum is σ = 1322200021032. Its totient is φ = 1322200021030.
The previous prime is 1322200020983. The next prime is 1322200021039. The reversal of 1322200021031 is 1301200022231.
It is a strong prime.
It is an emirp because it is prime and its reverse (1301200022231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1322200021031 is a prime.
It is a super-2 number, since 2×13222000210312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1322200021039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661100010515 + 661100010516.
It is an arithmetic number, because the mean of its divisors is an integer number (661100010516).
Almost surely, 21322200021031 is an apocalyptic number.
1322200021031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1322200021031 is an equidigital number, since it uses as much as digits as its factorization.
1322200021031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 1322200021031 its reverse (1301200022231), we get a palindrome (2623400043262).
The spelling of 1322200021031 in words is "one trillion, three hundred twenty-two billion, two hundred million, twenty-one thousand, thirty-one".
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