Base | Representation |
---|---|
bin | 11110000100000011100101… |
… | …111010110000110001100111 |
3 | 122100011010021020110121120121 |
4 | 132010003211322300301213 |
5 | 114312243311420023123 |
6 | 1145113031154142411 |
7 | 36564406044521302 |
oct | 3604034572606147 |
9 | 570133236417517 |
10 | 132220130626663 |
11 | 39147273848a52 |
12 | 129b5192281a07 |
13 | 58a13c68bb121 |
14 | 24916ba4d9b39 |
15 | 1044537e6a75d |
hex | 7840e5eb0c67 |
132220130626663 has 2 divisors, whose sum is σ = 132220130626664. Its totient is φ = 132220130626662.
The previous prime is 132220130626609. The next prime is 132220130626681. The reversal of 132220130626663 is 366626031022231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132220130626663 - 217 = 132220130495591 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132220130626693) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66110065313331 + 66110065313332.
It is an arithmetic number, because the mean of its divisors is an integer number (66110065313332).
Almost surely, 2132220130626663 is an apocalyptic number.
132220130626663 is a deficient number, since it is larger than the sum of its proper divisors (1).
132220130626663 is an equidigital number, since it uses as much as digits as its factorization.
132220130626663 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 559872, while the sum is 43.
Adding to 132220130626663 its reverse (366626031022231), we get a palindrome (498846161648894).
The spelling of 132220130626663 in words is "one hundred thirty-two trillion, two hundred twenty billion, one hundred thirty million, six hundred twenty-six thousand, six hundred sixty-three".
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