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132220150342243 is a prime number
BaseRepresentation
bin11110000100000011100111…
…000101111110001001100011
3122100011010022121120021021021
4132010003213011332021203
5114312243331441422433
61145113033140510311
736564406404224155
oct3604034705761143
9570133277507237
10132220150342243
1139147283994617
12129b51989ab397
1358a13caa01c52
1424916bcd8cad5
151044539a6222d
hex7840e717e263

132220150342243 has 2 divisors, whose sum is σ = 132220150342244. Its totient is φ = 132220150342242.

The previous prime is 132220150342171. The next prime is 132220150342277. The reversal of 132220150342243 is 342243051022231.

It is an a-pointer prime, because the next prime (132220150342277) can be obtained adding 132220150342243 to its sum of digits (34).

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132220150342243 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132220150342199 and 132220150342208.

It is not a weakly prime, because it can be changed into another prime (132220150342843) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66110075171121 + 66110075171122.

It is an arithmetic number, because the mean of its divisors is an integer number (66110075171122).

Almost surely, 2132220150342243 is an apocalyptic number.

132220150342243 is a deficient number, since it is larger than the sum of its proper divisors (1).

132220150342243 is an equidigital number, since it uses as much as digits as its factorization.

132220150342243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 34.

The spelling of 132220150342243 in words is "one hundred thirty-two trillion, two hundred twenty billion, one hundred fifty million, three hundred forty-two thousand, two hundred forty-three".