13222110113 has 4 divisors (see below), whose sum is σ = 13408337088. Its totient is φ = 13035883140.

The previous prime is 13222110079. The next prime is 13222110149. The reversal of 13222110113 is 31101122231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31101122231 = 53 ⋅586813627.

It is a cyclic number.

It is not a de Polignac number, because 13222110113 - 2²⁴ = 13205332897 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13222110091 and 13222110100.

It is not an unprimeable number, because it can be changed into a prime (13222110193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93113381 + ... + 93113522.

It is an arithmetic number, because the mean of its divisors is an integer number (3352084272).

Almost surely, 2^13222110113 is an apocalyptic number.

It is an amenable number.

13222110113 is a deficient number, since it is larger than the sum of its proper divisors (186226975).

13222110113 is an equidigital number, since it uses as much as digits as its factorization.

13222110113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 186226974.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13222110113 its reverse (31101122231), we get a palindrome (44323232344).

The spelling of 13222110113 in words is "thirteen billion, two hundred twenty-two million, one hundred ten thousand, one hundred thirteen".