Base | Representation |
---|---|
bin | 1100000001101000111011… |
… | …0000000100110001010110 |
3 | 1201211001002010021021011011 |
4 | 3000122032300010301112 |
5 | 3213113234400213324 |
6 | 44042124233202434 |
7 | 2533165012121365 |
oct | 300321660046126 |
9 | 51731063237134 |
10 | 13222304304214 |
11 | 4238603090865 |
12 | 15966a2b6041a |
13 | 74bb1cba3525 |
14 | 339d6a45b7dc |
15 | 17de20ce8c94 |
hex | c068ec04c56 |
13222304304214 has 4 divisors (see below), whose sum is σ = 19833456456324. Its totient is φ = 6611152152106.
The previous prime is 13222304304203. The next prime is 13222304304229. The reversal of 13222304304214 is 41240340322231.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×132223043042142 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3305576076052 + ... + 3305576076055.
It is an arithmetic number, because the mean of its divisors is an integer number (4958364114081).
Almost surely, 213222304304214 is an apocalyptic number.
13222304304214 is a deficient number, since it is larger than the sum of its proper divisors (6611152152110).
13222304304214 is an equidigital number, since it uses as much as digits as its factorization.
13222304304214 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6611152152109.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 13222304304214 its reverse (41240340322231), we get a palindrome (54462644626445).
The spelling of 13222304304214 in words is "thirteen trillion, two hundred twenty-two billion, three hundred four million, three hundred four thousand, two hundred fourteen".
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