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132223111310431 is a prime number
BaseRepresentation
bin11110000100000110010111…
…100101001010110001011111
3122100011101221222011001000201
4132010012113211022301133
5114312320412443413211
61145114243032404331
736564542650103401
oct3604062745126137
9570141858131021
10132223111310431
1139148563315869
12129b58845466a7
1358a178029b52b
1424918c0314b71
15104465e9960c1
hex78419794ac5f

132223111310431 has 2 divisors, whose sum is σ = 132223111310432. Its totient is φ = 132223111310430.

The previous prime is 132223111310417. The next prime is 132223111310467. The reversal of 132223111310431 is 134013111322231.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132223111310431 - 25 = 132223111310399 is a prime.

It is a super-2 number, since 2×1322231113104312 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 132223111310431.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132223111310531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66111555655215 + 66111555655216.

It is an arithmetic number, because the mean of its divisors is an integer number (66111555655216).

Almost surely, 2132223111310431 is an apocalyptic number.

132223111310431 is a deficient number, since it is larger than the sum of its proper divisors (1).

132223111310431 is an equidigital number, since it uses as much as digits as its factorization.

132223111310431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 28.

Adding to 132223111310431 its reverse (134013111322231), we get a palindrome (266236222632662).

The spelling of 132223111310431 in words is "one hundred thirty-two trillion, two hundred twenty-three billion, one hundred eleven million, three hundred ten thousand, four hundred thirty-one".