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132223311000000 = 263256113736097
BaseRepresentation
bin11110000100000110100011…
…011110111011000111000000
3122100011102110212220022121200
4132010012203132323013000
5114312321320104000000
61145114314524421200
736564550623325623
oct3604064336730700
9570142425808550
10132223311000000
1139148656006570
12129b591b3a7800
1358a17b277743c
1424918dca55dba
15104467228d500
hex7841a37bb1c0

132223311000000 has 1176 divisors, whose sum is σ = 530786094288528. Its totient is φ = 31186944000000.

The previous prime is 132223310999987. The next prime is 132223311000013. The reversal of 132223311000000 is 113322231.

132223311000000 is a `hidden beast` number, since 1 + 322 + 2 + 331 + 10 + 0 + 0 + 0 + 0 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (132223310999987) and next prime (132223311000013).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 167 ways as a sum of consecutive naturals, for example, 3662981952 + ... + 3663018048.

Almost surely, 2132223311000000 is an apocalyptic number.

132223311000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132223311000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (265393047144264).

132223311000000 is an abundant number, since it is smaller than the sum of its proper divisors (398562783288528).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132223311000000 is an equidigital number, since it uses as much as digits as its factorization.

132223311000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36193 (or 36155 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 132223311000000 its reverse (113322231), we get a palindrome (132223424322231).

The spelling of 132223311000000 in words is "one hundred thirty-two trillion, two hundred twenty-three billion, three hundred eleven million", and thus it is an aban number.