Base | Representation |
---|---|
bin | 11000101000001111… |
… | …00001111101101101 |
3 | 1021010111022112210121 |
4 | 30110013201331231 |
5 | 204034414422313 |
6 | 10024014204541 |
7 | 645443501263 |
oct | 142407417555 |
9 | 37114275717 |
10 | 13222420333 |
11 | 5675791111 |
12 | 26901b3751 |
13 | 13294a8c75 |
14 | 8d6106433 |
15 | 525c3928d |
hex | 3141e1f6d |
13222420333 has 2 divisors, whose sum is σ = 13222420334. Its totient is φ = 13222420332.
The previous prime is 13222420303. The next prime is 13222420363. The reversal of 13222420333 is 33302422231.
It is a balanced prime because it is at equal distance from previous prime (13222420303) and next prime (13222420363).
It can be written as a sum of positive squares in only one way, i.e., 11121389764 + 2101030569 = 105458^2 + 45837^2 .
It is a cyclic number.
It is not a de Polignac number, because 13222420333 - 25 = 13222420301 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13222420298 and 13222420307.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13222420303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6611210166 + 6611210167.
It is an arithmetic number, because the mean of its divisors is an integer number (6611210167).
Almost surely, 213222420333 is an apocalyptic number.
It is an amenable number.
13222420333 is a deficient number, since it is larger than the sum of its proper divisors (1).
13222420333 is an equidigital number, since it uses as much as digits as its factorization.
13222420333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 13222420333 its reverse (33302422231), we get a palindrome (46524842564).
The spelling of 13222420333 in words is "thirteen billion, two hundred twenty-two million, four hundred twenty thousand, three hundred thirty-three".
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