Base | Representation |
---|---|
bin | 1100000001101001010110… |
… | …1110000011010011000000 |
3 | 1201211001101021020220210001 |
4 | 3000122111232003103000 |
5 | 3213114004312330100 |
6 | 44042144011045344 |
7 | 2533200631623406 |
oct | 300322556032300 |
9 | 51731337226701 |
10 | 13222421214400 |
11 | 4238663082152 |
12 | 1596716140854 |
13 | 74bb3b187c58 |
14 | 339d7bbb1476 |
15 | 17de2b1ddd6a |
hex | c0695b834c0 |
13222421214400 has 168 divisors, whose sum is σ = 35289497483856. Its totient is φ = 4856441241600.
The previous prime is 13222421214347. The next prime is 13222421214413. The reversal of 13222421214400 is 441212422231.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4813074 + ... + 7043473.
It is an arithmetic number, because the mean of its divisors is an integer number (210056532642).
Almost surely, 213222421214400 is an apocalyptic number.
13222421214400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13222421214400 is an abundant number, since it is smaller than the sum of its proper divisors (22067076269456).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13222421214400 is a wasteful number, since it uses less digits than its factorization.
13222421214400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11856627 (or 11856612 counting only the distinct ones).
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 13222421214400 its reverse (441212422231), we get a palindrome (13663633636631).
The spelling of 13222421214400 in words is "thirteen trillion, two hundred twenty-two billion, four hundred twenty-one million, two hundred fourteen thousand, four hundred".
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