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1322250021431 is a prime number
BaseRepresentation
bin10011001111011100001…
…111100010101000110111
311200101221212200122121222
4103033130033202220313
5133130432001141211
62451233330500555
7164346405511463
oct23173417425067
94611855618558
101322250021431
1146a843736659
12194316a3475b
13978c29987b1
1447dd660d4a3
15245dc48e1db
hex133dc3e2a37

1322250021431 has 2 divisors, whose sum is σ = 1322250021432. Its totient is φ = 1322250021430.

The previous prime is 1322250021409. The next prime is 1322250021481. The reversal of 1322250021431 is 1341200522231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1322250021431 - 210 = 1322250020407 is a prime.

It is a super-2 number, since 2×13222500214312 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1322250021431.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1322250021481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661125010715 + 661125010716.

It is an arithmetic number, because the mean of its divisors is an integer number (661125010716).

Almost surely, 21322250021431 is an apocalyptic number.

1322250021431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1322250021431 is an equidigital number, since it uses as much as digits as its factorization.

1322250021431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 26.

Adding to 1322250021431 its reverse (1341200522231), we get a palindrome (2663450543662).

The spelling of 1322250021431 in words is "one trillion, three hundred twenty-two billion, two hundred fifty million, twenty-one thousand, four hundred thirty-one".