Base | Representation |
---|---|
bin | 11110000100001000100110… |
… | …000101010111100011010111 |
3 | 122100011122010120212112210011 |
4 | 132010020212011113203113 |
5 | 114312340312020203210 |
6 | 1145115320155541051 |
7 | 36564656130444235 |
oct | 3604104605274327 |
9 | 570148116775704 |
10 | 132225502116055 |
11 | 3914957a918487 |
12 | 129b623115a787 |
13 | 58a1a716b820a |
14 | 2491a69a5d955 |
15 | 104474e802d8a |
hex | 7842261578d7 |
132225502116055 has 8 divisors (see below), whose sum is σ = 159644041819632. Its totient is φ = 105131442172608.
The previous prime is 132225502116041. The next prime is 132225502116107. The reversal of 132225502116055 is 550611205522231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132225502116055 - 215 = 132225502083287 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132225502115999 and 132225502116017.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 81119939134 + ... + 81119940763.
It is an arithmetic number, because the mean of its divisors is an integer number (19955505227454).
Almost surely, 2132225502116055 is an apocalyptic number.
132225502116055 is a deficient number, since it is larger than the sum of its proper divisors (27418539703577).
132225502116055 is a wasteful number, since it uses less digits than its factorization.
132225502116055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 162239880065.
The product of its (nonzero) digits is 180000, while the sum is 40.
Adding to 132225502116055 its reverse (550611205522231), we get a palindrome (682836707638286).
The spelling of 132225502116055 in words is "one hundred thirty-two trillion, two hundred twenty-five billion, five hundred two million, one hundred sixteen thousand, fifty-five".
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