Base | Representation |
---|---|
bin | 11000101000010000… |
… | …00010110111100101 |
3 | 1021010111120101200022 |
4 | 30110020002313211 |
5 | 204034433230414 |
6 | 10024021124525 |
7 | 645444602231 |
oct | 142410026745 |
9 | 37114511608 |
10 | 13222555109 |
11 | 56758733a5 |
12 | 2690259745 |
13 | 132952540a |
14 | 8d613d5c1 |
15 | 525c6418e |
hex | 314202de5 |
13222555109 has 2 divisors, whose sum is σ = 13222555110. Its totient is φ = 13222555108.
The previous prime is 13222555037. The next prime is 13222555111. The reversal of 13222555109 is 90155522231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10797288100 + 2425267009 = 103910^2 + 49247^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13222555109 is a prime.
It is a super-2 number, since 2×132225551092 (a number of 21 digits) contains 22 as substring.
Together with 13222555111, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13222585109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6611277554 + 6611277555.
It is an arithmetic number, because the mean of its divisors is an integer number (6611277555).
Almost surely, 213222555109 is an apocalyptic number.
It is an amenable number.
13222555109 is a deficient number, since it is larger than the sum of its proper divisors (1).
13222555109 is an equidigital number, since it uses as much as digits as its factorization.
13222555109 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27000, while the sum is 35.
The spelling of 13222555109 in words is "thirteen billion, two hundred twenty-two million, five hundred fifty-five thousand, one hundred nine".
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