1322256112739 has 2 divisors, whose sum is σ = 1322256112740. Its totient is φ = 1322256112738.

The previous prime is 1322256112733. The next prime is 1322256112741. The reversal of 1322256112739 is 9372116522231.

It is a strong prime.

It is an emirp because it is prime and its reverse (9372116522231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1322256112739 is a prime.

It is a super-2 number, since 2×1322256112739² (a number of 25 digits) contains 22 as substring.

Together with 1322256112741, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1322256112739.

It is not a weakly prime, because it can be changed into another prime (1322256112733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661128056369 + 661128056370.

It is an arithmetic number, because the mean of its divisors is an integer number (661128056370).

Almost surely, 2^{1322256112739} is an apocalyptic number.

1322256112739 is a deficient number, since it is larger than the sum of its proper divisors (1).

1322256112739 is an equidigital number, since it uses as much as digits as its factorization.

1322256112739 is an evil number, because the sum of its binary digits is even.

The product of its digits is 272160, while the sum is 44.

The spelling of 1322256112739 in words is "one trillion, three hundred twenty-two billion, two hundred fifty-six million, one hundred twelve thousand, seven hundred thirty-nine".