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1322256112733 is a prime number
BaseRepresentation
bin10011001111011100100…
…110110001110001011101
311200101222022011010022202
4103033130212301301131
5133130440031101413
62451234105221245
7164346511341413
oct23173446616135
94611868133282
101322256112733
1146a847117096
12194318a91825
13978c401c20a
1447dd73572b3
15245dcc93e58
hex133dc9b1c5d

1322256112733 has 2 divisors, whose sum is σ = 1322256112734. Its totient is φ = 1322256112732.

The previous prime is 1322256112703. The next prime is 1322256112739. The reversal of 1322256112733 is 3372116522231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1246610211289 + 75645901444 = 1116517^2 + 275038^2 .

It is a cyclic number.

It is not a de Polignac number, because 1322256112733 - 216 = 1322256047197 is a prime.

It is a super-2 number, since 2×13222561127332 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1322256112739) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661128056366 + 661128056367.

It is an arithmetic number, because the mean of its divisors is an integer number (661128056367).

Almost surely, 21322256112733 is an apocalyptic number.

It is an amenable number.

1322256112733 is a deficient number, since it is larger than the sum of its proper divisors (1).

1322256112733 is an equidigital number, since it uses as much as digits as its factorization.

1322256112733 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 90720, while the sum is 38.

The spelling of 1322256112733 in words is "one trillion, three hundred twenty-two billion, two hundred fifty-six million, one hundred twelve thousand, seven hundred thirty-three".