Base | Representation |
---|---|
bin | 111101100100111101… |
… | …0011011000111110101 |
3 | 110122022210101222221121 |
4 | 1323021322123013311 |
5 | 4131310024222431 |
6 | 140425412143541 |
7 | 12360642112054 |
oct | 1731172330765 |
9 | 418283358847 |
10 | 132236554741 |
11 | 510990a6885 |
12 | 21765907bb1 |
13 | c6153647c5 |
14 | 658654039b |
15 | 368e3a1611 |
hex | 1ec9e9b1f5 |
132236554741 has 4 divisors (see below), whose sum is σ = 133047822112. Its totient is φ = 131425287372.
The previous prime is 132236554717. The next prime is 132236554757. The reversal of 132236554741 is 147455632231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132236554741 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132236654741) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 405633441 + ... + 405633766.
It is an arithmetic number, because the mean of its divisors is an integer number (33261955528).
Almost surely, 2132236554741 is an apocalyptic number.
It is an amenable number.
132236554741 is a deficient number, since it is larger than the sum of its proper divisors (811267371).
132236554741 is an equidigital number, since it uses as much as digits as its factorization.
132236554741 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 811267370.
The product of its digits is 604800, while the sum is 43.
The spelling of 132236554741 in words is "one hundred thirty-two billion, two hundred thirty-six million, five hundred fifty-four thousand, seven hundred forty-one".
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