Base | Representation |
---|---|
bin | 111101100101000100… |
… | …0011111011010001101 |
3 | 110122100001100100100111 |
4 | 1323022020133122031 |
5 | 4131312000223232 |
6 | 140430023200021 |
7 | 12361015341031 |
oct | 1731210373215 |
9 | 418301310314 |
10 | 132240242317 |
11 | 510a0195367 |
12 | 21766ba6011 |
13 | c6160560c1 |
14 | 6586c201c1 |
15 | 368e87e047 |
hex | 1eca21f68d |
132240242317 has 2 divisors, whose sum is σ = 132240242318. Its totient is φ = 132240242316.
The previous prime is 132240242297. The next prime is 132240242347. The reversal of 132240242317 is 713242042231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 70431321321 + 61808920996 = 265389^2 + 248614^2 .
It is an emirp because it is prime and its reverse (713242042231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132240242317 - 219 = 132239718029 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132240242347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66120121158 + 66120121159.
It is an arithmetic number, because the mean of its divisors is an integer number (66120121159).
Almost surely, 2132240242317 is an apocalyptic number.
It is an amenable number.
132240242317 is a deficient number, since it is larger than the sum of its proper divisors (1).
132240242317 is an equidigital number, since it uses as much as digits as its factorization.
132240242317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 132240242317 its reverse (713242042231), we get a palindrome (845482284548).
The spelling of 132240242317 in words is "one hundred thirty-two billion, two hundred forty million, two hundred forty-two thousand, three hundred seventeen".
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