Base | Representation |
---|---|
bin | 111101100101000111… |
… | …1101000100010000001 |
3 | 110122100011212110202121 |
4 | 1323022033220202001 |
5 | 4131312440132224 |
6 | 140430131244241 |
7 | 12361040266606 |
oct | 1731217504201 |
9 | 418304773677 |
10 | 132242114689 |
11 | 510a1254083 |
12 | 21767749681 |
13 | c616560409 |
14 | 658718a6ad |
15 | 368eaedbe4 |
hex | 1eca3e8881 |
132242114689 has 2 divisors, whose sum is σ = 132242114690. Its totient is φ = 132242114688.
The previous prime is 132242114687. The next prime is 132242114699. The reversal of 132242114689 is 986411242231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 66594963600 + 65647151089 = 258060^2 + 256217^2 .
It is a cyclic number.
It is not a de Polignac number, because 132242114689 - 21 = 132242114687 is a prime.
Together with 132242114687, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (132242114687) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66121057344 + 66121057345.
It is an arithmetic number, because the mean of its divisors is an integer number (66121057345).
Almost surely, 2132242114689 is an apocalyptic number.
It is an amenable number.
132242114689 is a deficient number, since it is larger than the sum of its proper divisors (1).
132242114689 is an equidigital number, since it uses as much as digits as its factorization.
132242114689 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 165888, while the sum is 43.
The spelling of 132242114689 in words is "one hundred thirty-two billion, two hundred forty-two million, one hundred fourteen thousand, six hundred eighty-nine".
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