Base | Representation |
---|---|
bin | 11000101000011101… |
… | …01101101001100011 |
3 | 1021010121212012121112 |
4 | 30110032231221203 |
5 | 204040410200303 |
6 | 10024122413535 |
7 | 645465502556 |
oct | 142416555143 |
9 | 37117765545 |
10 | 13224303203 |
11 | 5676857801 |
12 | 26909612ab |
13 | 13299b7ca7 |
14 | 8d647669d |
15 | 525eac0d8 |
hex | 3143ada63 |
13224303203 has 2 divisors, whose sum is σ = 13224303204. Its totient is φ = 13224303202.
The previous prime is 13224303199. The next prime is 13224303223. The reversal of 13224303203 is 30230342231.
13224303203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (30230342231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13224303203 - 22 = 13224303199 is a prime.
It is not a weakly prime, because it can be changed into another prime (13224303223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6612151601 + 6612151602.
It is an arithmetic number, because the mean of its divisors is an integer number (6612151602).
Almost surely, 213224303203 is an apocalyptic number.
13224303203 is a deficient number, since it is larger than the sum of its proper divisors (1).
13224303203 is an equidigital number, since it uses as much as digits as its factorization.
13224303203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 23.
Adding to 13224303203 its reverse (30230342231), we get a palindrome (43454645434).
The spelling of 13224303203 in words is "thirteen billion, two hundred twenty-four million, three hundred three thousand, two hundred three".
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