Base | Representation |
---|---|
bin | 11110000100011010001101… |
… | …001100111100010111101100 |
3 | 122100020102221110012102021012 |
4 | 132010122031030330113230 |
5 | 114313143023434234200 |
6 | 1145132124424524352 |
7 | 36566225545143122 |
oct | 3604321514742754 |
9 | 570212843172235 |
10 | 132244412024300 |
11 | 391565a3a8a424 |
12 | 129b9a2a0206b8 |
13 | 58a37962a1034 |
14 | 2492941265912 |
15 | 1044ea99e3a35 |
hex | 78468d33c5ec |
132244412024300 has 18 divisors (see below), whose sum is σ = 286970374092948. Its totient is φ = 52897764809680.
The previous prime is 132244412024293. The next prime is 132244412024311. The reversal of 132244412024300 is 3420214442231.
It is a happy number.
132244412024300 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 661222060022 + ... + 661222060221.
Almost surely, 2132244412024300 is an apocalyptic number.
132244412024300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132244412024300 is an abundant number, since it is smaller than the sum of its proper divisors (154725962068648).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132244412024300 is a wasteful number, since it uses less digits than its factorization.
132244412024300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1322444120257 (or 1322444120250 counting only the distinct ones).
The product of its (nonzero) digits is 36864, while the sum is 32.
Adding to 132244412024300 its reverse (3420214442231), we get a palindrome (135664626466531).
The spelling of 132244412024300 in words is "one hundred thirty-two trillion, two hundred forty-four billion, four hundred twelve million, twenty-four thousand, three hundred".
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