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132254012220623 is a prime number
BaseRepresentation
bin11110000100100011001001…
…011010110010010011001111
3122100021100201111122220211222
4132010203021122302103033
5114313322204112024443
61145140353210233555
736600015466361516
oct3604431132622317
9570240644586758
10132254012220623
113915a680052a77
12129bb8691258bb
1358a46661b8387
1424931b227567d
15104536c72b468
hex7848c96b24cf

132254012220623 has 2 divisors, whose sum is σ = 132254012220624. Its totient is φ = 132254012220622.

The previous prime is 132254012220541. The next prime is 132254012220709. The reversal of 132254012220623 is 326022210452231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132254012220623 - 210 = 132254012219599 is a prime.

It is a super-2 number, since 2×1322540122206232 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132254012220223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66127006110311 + 66127006110312.

It is an arithmetic number, because the mean of its divisors is an integer number (66127006110312).

Almost surely, 2132254012220623 is an apocalyptic number.

132254012220623 is a deficient number, since it is larger than the sum of its proper divisors (1).

132254012220623 is an equidigital number, since it uses as much as digits as its factorization.

132254012220623 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 132254012220623 its reverse (326022210452231), we get a palindrome (458276222672854).

The spelling of 132254012220623 in words is "one hundred thirty-two trillion, two hundred fifty-four billion, twelve million, two hundred twenty thousand, six hundred twenty-three".