Base | Representation |
---|---|
bin | 11110000100100011010010… |
… | …011010011001011000011111 |
3 | 122100021101010000121001222011 |
4 | 132010203102122121120133 |
5 | 114313323011224113003 |
6 | 1145140420200332051 |
7 | 36600022311060454 |
oct | 3604432232313037 |
9 | 570241100531864 |
10 | 132254163113503 |
11 | 3915a748245032 |
12 | 129bb8ab774027 |
13 | 58a468b53a7c2 |
14 | 24931c831382b |
15 | 104537aad546d |
hex | 7848d269961f |
132254163113503 has 4 divisors (see below), whose sum is σ = 132307555995720. Its totient is φ = 132200770231288.
The previous prime is 132254163113489. The next prime is 132254163113507. The reversal of 132254163113503 is 305311361452231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132254163113503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132254163113507) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26696437393 + ... + 26696442346.
It is an arithmetic number, because the mean of its divisors is an integer number (33076888998930).
Almost surely, 2132254163113503 is an apocalyptic number.
132254163113503 is a deficient number, since it is larger than the sum of its proper divisors (53392882217).
132254163113503 is an equidigital number, since it uses as much as digits as its factorization.
132254163113503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53392882216.
The product of its (nonzero) digits is 194400, while the sum is 40.
The spelling of 132254163113503 in words is "one hundred thirty-two trillion, two hundred fifty-four billion, one hundred sixty-three million, one hundred thirteen thousand, five hundred three".
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