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132254331025351 = 1715894148946883
BaseRepresentation
bin11110000100100011011100…
…011010111011011111000111
3122100021101112201112212201111
4132010203130122323133013
5114313323332220302401
61145140444555305451
736600026420231413
oct3604433432733707
9570241481485644
10132254331025351
113915a824000757
12129bb937a4b287
1358a46b726b522
142493202741d43
15104538a701e51
hex7848dc6bb7c7

132254331025351 has 8 divisors (see below), whose sum is σ = 140034881461104. Its totient is φ = 124473878801280.

The previous prime is 132254331025259. The next prime is 132254331025387. The reversal of 132254331025351 is 153520133452231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132254331025351 - 29 = 132254331024839 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132254331025451) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21771445 + ... + 27175438.

It is an arithmetic number, because the mean of its divisors is an integer number (17504360182638).

Almost surely, 2132254331025351 is an apocalyptic number.

132254331025351 is a deficient number, since it is larger than the sum of its proper divisors (7780550435753).

132254331025351 is a wasteful number, since it uses less digits than its factorization.

132254331025351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49105841.

The product of its (nonzero) digits is 324000, while the sum is 40.

Adding to 132254331025351 its reverse (153520133452231), we get a palindrome (285774464477582).

The spelling of 132254331025351 in words is "one hundred thirty-two trillion, two hundred fifty-four billion, three hundred thirty-one million, twenty-five thousand, three hundred fifty-one".

Divisors: 1 17 158941 2701997 48946883 832097011 7779666530903 132254331025351