Base | Representation |
---|---|
bin | 111101100101110011… |
… | …1011001011111001101 |
3 | 110122101210011100111122 |
4 | 1323023213121133031 |
5 | 4131334332343431 |
6 | 140432312330325 |
7 | 12361436661554 |
oct | 1731347313715 |
9 | 418353140448 |
10 | 132265121741 |
11 | 51103238675 |
12 | 217733a39a5 |
13 | c61b25745c |
14 | 658a258d9b |
15 | 3691b45a7b |
hex | 1ecb9d97cd |
132265121741 has 4 divisors (see below), whose sum is σ = 138015779232. Its totient is φ = 126514464252.
The previous prime is 132265121617. The next prime is 132265121753. The reversal of 132265121741 is 147121562231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132265121741 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132265121771) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2875328711 + ... + 2875328756.
It is an arithmetic number, because the mean of its divisors is an integer number (34503944808).
Almost surely, 2132265121741 is an apocalyptic number.
It is an amenable number.
132265121741 is a deficient number, since it is larger than the sum of its proper divisors (5750657491).
132265121741 is an equidigital number, since it uses as much as digits as its factorization.
132265121741 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5750657490.
The product of its digits is 20160, while the sum is 35.
Adding to 132265121741 its reverse (147121562231), we get a palindrome (279386683972).
The spelling of 132265121741 in words is "one hundred thirty-two billion, two hundred sixty-five million, one hundred twenty-one thousand, seven hundred forty-one".
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