13230000113 has 4 divisors (see below), whose sum is σ = 14432727408. Its totient is φ = 12027272820.

The previous prime is 13230000101. The next prime is 13230000139. The reversal of 13230000113 is 31100003231.

13230000113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13230000113 - 2⁸ = 13229999857 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13230000193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 601363631 + ... + 601363652.

It is an arithmetic number, because the mean of its divisors is an integer number (3608181852).

Almost surely, 2^13230000113 is an apocalyptic number.

It is an amenable number.

13230000113 is a deficient number, since it is larger than the sum of its proper divisors (1202727295).

13230000113 is a wasteful number, since it uses less digits than its factorization.

13230000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1202727294.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 13230000113 its reverse (31100003231), we get a palindrome (44330003344).

The spelling of 13230000113 in words is "thirteen billion, two hundred thirty million, one hundred thirteen", and thus it is an aban number.