Base | Representation |
---|---|
bin | 10011010000001000111… |
… | …100111010011111001110 |
3 | 11200110220011010020221222 |
4 | 103100020330322133032 |
5 | 133134001012104402 |
6 | 2451440003523342 |
7 | 164404114261613 |
oct | 23201074723716 |
9 | 4613804106858 |
10 | 1323000113102 |
11 | 470099089628 |
12 | 1944a6089552 |
13 | 979b21c5c15 |
14 | 480680a650a |
15 | 246332587a2 |
hex | 13408f3a7ce |
1323000113102 has 4 divisors (see below), whose sum is σ = 1984500169656. Its totient is φ = 661500056550.
The previous prime is 1323000113087. The next prime is 1323000113107. The reversal of 1323000113102 is 2013110003231.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1323000113107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 330750028274 + ... + 330750028277.
It is an arithmetic number, because the mean of its divisors is an integer number (496125042414).
Almost surely, 21323000113102 is an apocalyptic number.
1323000113102 is a deficient number, since it is larger than the sum of its proper divisors (661500056554).
1323000113102 is an equidigital number, since it uses as much as digits as its factorization.
1323000113102 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 661500056553.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 1323000113102 its reverse (2013110003231), we get a palindrome (3336110116333).
The spelling of 1323000113102 in words is "one trillion, three hundred twenty-three billion, one hundred thirteen thousand, one hundred two".
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