1323011020021 has 4 divisors (see below), whose sum is σ = 1323399344832. Its totient is φ = 1322622695212.

The previous prime is 1323011019959. The next prime is 1323011020073. The reversal of 1323011020021 is 1200201103231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1323011020021 - 2¹⁵ = 1323010987253 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1323011019977 and 1323011020004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1323011020091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 194157295 + ... + 194164108.

It is an arithmetic number, because the mean of its divisors is an integer number (330849836208).

Almost surely, 2^{1323011020021} is an apocalyptic number.

It is an amenable number.

1323011020021 is a deficient number, since it is larger than the sum of its proper divisors (388324811).

1323011020021 is an equidigital number, since it uses as much as digits as its factorization.

1323011020021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 388324810.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1323011020021 its reverse (1200201103231), we get a palindrome (2523212123252).

The spelling of 1323011020021 in words is "one trillion, three hundred twenty-three billion, eleven million, twenty thousand, twenty-one".