Base | Representation |
---|---|
bin | 111101100110111110… |
… | …0100111111000010011 |
3 | 110122111111202202212111 |
4 | 1323031330213320103 |
5 | 4131424341141042 |
6 | 140440231010151 |
7 | 12362423325442 |
oct | 1731574477023 |
9 | 418444682774 |
10 | 132304240147 |
11 | 51123326932 |
12 | 21784509957 |
13 | c6263a2941 |
14 | 659151cd59 |
15 | 36952c1517 |
hex | 1ecdf27e13 |
132304240147 has 2 divisors, whose sum is σ = 132304240148. Its totient is φ = 132304240146.
The previous prime is 132304240063. The next prime is 132304240267. The reversal of 132304240147 is 741042403231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132304240147 - 223 = 132295851539 is a prime.
It is not a weakly prime, because it can be changed into another prime (132304243147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66152120073 + 66152120074.
It is an arithmetic number, because the mean of its divisors is an integer number (66152120074).
Almost surely, 2132304240147 is an apocalyptic number.
132304240147 is a deficient number, since it is larger than the sum of its proper divisors (1).
132304240147 is an equidigital number, since it uses as much as digits as its factorization.
132304240147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 132304240147 its reverse (741042403231), we get a palindrome (873346643378).
The spelling of 132304240147 in words is "one hundred thirty-two billion, three hundred four million, two hundred forty thousand, one hundred forty-seven".
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