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132311002122113 is a prime number
BaseRepresentation
bin11110000101011000001110…
…010010000000011110000001
3122100110210211020012212201012
4132011120032102000132001
5114320240413020401423
61145222500225450305
736604103655504023
oct3605301622003601
9570423736185635
10132311002122113
11391818653a2511
1212a0a912aa0995
1358a9b49136689
142495c5b054013
151046aa5a93078
hex78560e480781

132311002122113 has 2 divisors, whose sum is σ = 132311002122114. Its totient is φ = 132311002122112.

The previous prime is 132311002122031. The next prime is 132311002122193. The reversal of 132311002122113 is 311221200113231.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101079356915329 + 31231645206784 = 10053823^2 + 5588528^2 .

It is a cyclic number.

It is not a de Polignac number, because 132311002122113 - 212 = 132311002118017 is a prime.

It is not a weakly prime, because it can be changed into another prime (132311002122193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66155501061056 + 66155501061057.

It is an arithmetic number, because the mean of its divisors is an integer number (66155501061057).

Almost surely, 2132311002122113 is an apocalyptic number.

It is an amenable number.

132311002122113 is a deficient number, since it is larger than the sum of its proper divisors (1).

132311002122113 is an equidigital number, since it uses as much as digits as its factorization.

132311002122113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 132311002122113 its reverse (311221200113231), we get a palindrome (443532202235344).

The spelling of 132311002122113 in words is "one hundred thirty-two trillion, three hundred eleven billion, two million, one hundred twenty-two thousand, one hundred thirteen".